Questions
A particle of mass ‘M’ moved under a constant power Po. At same instant after the start, its speed is V and at a later instant, the speed is 2V; Neglecting friction, distance travelled by the particle as its speed increases from V to 2V is
detailed solution
Correct option is D
power P=force . velocity P0=ma.v=mdvdtv=mdvdtdxdxv=mdvdxdxdtv=mdvdxv.v P0Mdx=v2dv integrating ∫0xP0Mdx=∫v2vv2dv P0Mx=v332vv x = M3Po [(2V)3−V3] x= =7MV33PoTalk to our academic expert!
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