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Q.

A particle of mass ‘M’ moved under a constant power Po.  At same instant after the start, its speed is V and at a later instant, the speed is 2V; Neglecting friction, distance travelled by the particle as its speed increases from V to 2V is

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a

12MV35Po

b

8PoV2M

c

9MV35Po

d

7MV33Po

answer is D.

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Detailed Solution

power P=force . velocity P0=ma.v=mdvdtv=mdvdtdxdxv=mdvdxdxdtv=mdvdxv.v P0Mdx=v2dv integrating ∫0xP0Mdx=∫v2vv2dv P0Mx=v332vv x   =    M3Po  [(2V)3−V3]  x= =7MV33Po
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