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Q.

A particle of mass ‘m’ moves on the axis of a ring of radius ‘R’ and mass M. If particle at rest is released from ‘P’  then its kinetic energy at centre c will be

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a

GmMR

b

GMm2R

c

GmM3R3-1

d

3GMmR

answer is B.

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Detailed Solution

distance of the mass m from the ring is (3R)2+R2 =2R initial potential energy = -GMm2R and final potential energy when at the center is -GMmRkinetic energy is the difference in potential energy
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