Questions
A particle of mass ‘m’ moves on the axis of a ring of radius ‘R’ and mass M. If particle at rest is released from ‘P’ then its kinetic energy at centre c will be
detailed solution
Correct option is B
distance of the mass m from the ring is (3R)2+R2 =2R initial potential energy = -GMm2R and final potential energy when at the center is -GMmRkinetic energy is the difference in potential energyTalk to our academic expert!
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The masses, each of mass m are kept on the vertices of an equilateral triangle of side a. Find the work needed to be done to change the length of the triangle twice of its original value.
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