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Q.

A particle of mass M is moving along a circular path of consultant radius R. The centripetal acceleration varies as a a=K2Rt2, where K is constant and t is the time elapsed. What is the power delivered to the particle by the force acting on it ?

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a

M4K2R2t

b

M2K2R2t

c

MK2R2t

d

2MK2R2t

answer is C.

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Detailed Solution

For circular motion, a=v2/R  Here K2Rt2=v2/R  or  v2=K2R2t2    Differentiating ,  2vdvdt=k2R22t   ⇒at = kR Therefore Power = Ft .v =M . kR . kRt =Mk2R2t
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