First slide

Work done by Diff type of forces

Question

A particle of mass 'm' is moving along X-axis under a force $F = k \sqrt{x}$ work done for the motion of particle from x = 4 m to x = 9 m is nearly:

Moderate

A

19.2 k
B

8.6 k
C

32.3 k
D

12.7 k

Solution

Work done $= \int Fdx = \int_{4}^{9} k \sqrt{x} dx$
$= \frac{2}{3} k {[x^{3 / 2}]}_{4}^{9} = \frac{38}{3} k = 12 .7 k$

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