A particle of mass M is moving in a circle of fixed radius ‘R’ in such a way that its centripetal acceleration at time ‘t’ is given by n2Rt2 . Where n is a constant, the power delivered to the particle by the force acting on it is
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a
−12 Mn2R2t2
b
Mn2R2t
c
MnR2t2
d
MnR2t
answer is B.
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Detailed Solution
∴ Centripetal Acceleration = n2Rt2 = Vt2R ∴ Vt2 = n2R2t2 ⇒ Vt = nRt---(1) differentiate with respect to time t dVtdt = nR---(2) Tangential Force on the particle is Ft = M dVtdt substitute equation (2) Ft = M n R---(3) here Vt is speed of the particle power delivered =Ft⋅Vt substitute equations (3) and (1) in above equation power delivered == MnR⋅nRt = Mn2R2⋅t