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Q.

A particle of mass M is moving in a circle of fixed radius ‘R’ in such a way that its centripetal acceleration at time ‘t’ is given by n2Rt2 . Where n is a constant,  the power delivered to the particle by the force acting on it is

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a

−12 Mn2R2t2

b

Mn2R2t

c

MnR2t2

d

MnR2t

answer is B.

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Detailed Solution

∴   Centripetal Acceleration =   n2Rt2 =  Vt2R   ∴   Vt2  =  n2R2t2  ⇒   Vt   =   nRt---(1) differentiate with respect to time t dVtdt  =   nR---(2)   Tangential Force on the particle is Ft  =   M dVtdt substitute equation (2) Ft  =   M n R---(3) here Vt is speed of the particle     power delivered  =Ft⋅Vt  substitute equations (3) and (1) in above equation   power delivered  ==   MnR⋅nRt   =   Mn2R2⋅t
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