A particle of mass ‘m is moving in a circular path of constant radius ‘r’ such that its centripetal acceleration is aC is varying with time t as aC=k2rt2 where k is a constant. What is the power delivered to the particle by the forces acting on it.

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mk2r2t

12mk2r2t2

14mk2r2t2

13mk2r2t2

answer is A.

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Detailed Solution

aC=v2r v2r=k2rt2 KE=12mv2=12mk2r2t2 Acc to work energy theoremW=Δk=12mk2r2t2 P=dwdt=ddt(12mk2r2t2) P=mk2r2t

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