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Q.

A particle of mass m is moving in a circular path of constant radius r such that its centripetal acceleration ac is varying with time t as ac=k2rt2 where k is a constant. The power delivered to the particle by the forces acting on it, is

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a

zero

b

mk2r2t2

c

mk2r2t

d

mk2rt

answer is C.

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Detailed Solution

ac=v2r=k2rt2 or v=krt tangential acceleration is, at=dvdt=kr hence ∴ P=Ftv cosθ=m atv cosθ
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A particle of mass m is moving in a circular path of constant radius r such that its centripetal acceleration ac is varying with time t as ac=k2rt2 where k is a constant. The power delivered to the particle by the forces acting on it, is