First slide

Types of collision

Question

. A particle of mass m moving eastward with a speed v collides with another particle of the same mass moving northward with the same speed v' . The two particles coalesce on collision. The new particle of mass 2 m will move in the north-easterly direction with a velocity

Moderate

A

$- v / 2$
B

v /2
C

$V / \sqrt{2}$
D

none of the above

Solution

Applying the law of conservation of momentum along X and Y axes, we get
$mv = (2 m) v^{'} \cos θ and mv = (2 m) v^{'} \sin θ ∴ \tan θ = 1 or θ = \tan^{- 1} (1) = 45^{\circ} Further V^{'} = \frac{V}{2 \cos θ} = \frac{\sqrt{2} \cdot V}{2} = \frac{V}{\sqrt{2}}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App