. A particle of mass m moving eastward with a speed v collides with another particle of the same mass moving northward with the same speed v' . The two particles coalesce on collision. The new particle of mass $$2$$ m will move in the $$north-easterly$$ direction with a velocity

Question

Infinity Learn · Accepted Answer

Applying the law of conservation of momentum along X and Y axes, we get $$mv=(2m)v$$′$$cos$$⁡θ and $$mv=(2m)v$$′$$sin$$⁡θ ∴ $$tan$$⁡θ$$=1$$  or  θ$$=$$$$tan$$−$$1$$⁡$$(1)=45$$∘  Further V′$$=V2cos$$⁡θ$$=2$$⋅$$V2=V2$$

. A particle of mass m moving eastward with a speed v collides with another particle of the same mass moving northward with the same speed v' . The two particles coalesce on collision. The new particle of mass 2 m will move in the north-easterly direction with a velocity

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