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Q.

. A particle of mass m moving eastward with a speed v collides with another particle of the same mass moving northward with the same speed v' . The two particles coalesce on collision. The new particle of mass 2 m will move in the north-easterly direction with a velocity

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a

−v/2

b

v /2

c

V/2

d

none of the above

answer is C.

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Detailed Solution

Applying the law of conservation of momentum along X and Y axes, we get mv=(2m)v′cos⁡θ and mv=(2m)v′sin⁡θ ∴ tan⁡θ=1 or θ=tan−1⁡(1)=45∘ Further V′=V2cos⁡θ=2⋅V2=V2

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