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A particle of mass m moving eastward with a speed v collides with another particle of the same mass moving northward with the same speed v. The two particles coalesce on collision. The new particle of mass 2m will move in the north-easterly direction with a velocity

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a
v/2
b
2v
c
v/2
d
v

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detailed solution

Correct option is C

Initial momentum of the system P→i=mvi^+mvj^ |P→i| = 2mvFinal momentum of the system = 2mVBy the law of conservation of momentum  2mv=2mV⇒V=v2

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