Questions
A particle of mass m is moving in a horizontal circle of radius r under a centripetal force equal to -k/r2, where k is a constant. The total energy of the particle is
detailed solution
Correct option is C
Centripetal force, F=mv2r=−kr2Negative sign shows that the force is directed towards the centre of the circle.∴ mv2=kr K.E. =12mv2=k/2r P.E. =−k/r∴ Total energy =k2r−kr=−k2rTalk to our academic expert!
Similar Questions
Statement -A : The net acceleration of a particle in circular motion is always along the radius of the circle towards the centre
Statement -B : The velocity vector of a particle at a point is always along the tangent to the path of the particle at that point
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