First slide
The two types of acceleration
Question

A particle of mass m is moving in a horizontal circle of radius r under a centripetal force equal to -k/r2, where k is a constant. The total energy of the particle is

Moderate
Solution

Centripetal force, F=mv2r=kr2

Negative sign shows that the force is directed towards the centre of the circle.

 mv2=kr K.E. =12mv2=k/2r P.E. =k/r  Total energy =k2rkr=k2r

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