A particle of mass m is moving in a horizontal circle of radius r under a centripetal force equal to −K/r2, where K is a constant. The total energy of the particle is

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K2r

−K2r

−Kr

answer is B.

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Detailed Solution

Here mv2r=Kr2 ∴ K.E. =12mv2=K2rU=−∫∞rF.dr=−∫∞r−Kr2 dr=−KrTotal energy E=K.E.+P.E.=K2r−Kr=−K2r

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