Questions
A particle of mass ‘m’ is moving horizontally with a constant velocity ‘v’ towards a massive rigid wall that is moving in opposite direction with a constant speed ‘u’. Assuming elastic impact between the particle and wall, the work done by the wall in reflecting the particle is equal to
detailed solution
Correct option is D
Velocity of separation = -e (velocity of approach)⇒(−v1i)−(-ui)=−e[(vi)−(−ui)]⇒u−v1=−1(v+u)⇒v1=2u+v ∴W=ΔK.E.=12mv1 2−12mv2=12m[(2u+v)2−v2]=2mu(u+v) .Talk to our academic expert!
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A body of mass m moving with velocity v makes a head-on collision with another body of mass 2 m which is initially at rest. The loss of kinetic energy of the colliding body (mass m) is
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