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Questions  

A particle of mass ‘m’ is moving horizontally with a constant velocity ‘v’ towards a massive rigid wall that is moving in opposite direction with a constant speed ‘u’. Assuming elastic impact between the particle and wall, the work done by the wall in reflecting the particle is equal to

a
12m(u+v)2
b
12m(u+v)
c
12muv
d
2mu(u+v)

detailed solution

Correct option is D

Velocity of separation = -e (velocity of approach)⇒(−v1i)−(-ui)=−e[(vi)−(−ui)]⇒u−v1=−1(v+u)⇒v1=2u+v                ∴W=ΔK.E.=12mv1 2−12mv2=12m[(2u+v)2−v2]=2mu(u+v) .

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