A particle of mass m is moving horizontally with a constant velocity v towards a rigid wall that is moving in opposite direction with a constant speed u. Assuming elastic impact between the particle and wall, the work done by the wall in reflecting the particle is equal to

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(1/2) m(u + v)2

(1/2) m(u + v)

(1/2) muv

None of these

answer is D.

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Detailed Solution

e=v2−v1u1−u2⇒1=−u−(−v')v−(−u)⇒v' = 2u + v∴W = ∆KE=12mv'212mv2 =12m[(2u + v)2] = 2 mu(u + v)

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