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A particle of mass m is moving horizontally with a constant velocity v towards a rigid wall that is moving in opposite direction with a constant speed u. Assuming elastic impact between the particle and wall, the work done by the wall in reflecting the particle is equal to

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a
(1/2) m(u + v)2
b
(1/2) m(u + v)
c
(1/2) muv
d
None of these

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detailed solution

Correct option is D

e=v2−v1u1−u2⇒1=−u−(−v')v−(−u)⇒v' = 2u + v∴W = ∆KE=12mv'212mv2 =12m[(2u + v)2] = 2 mu(u + v)


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