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A particle of mass m moving towards the east with speed v collides with another particle of the same mass and same speed v moving towards north. If the two particles stick to each other, the new particle of mass 2 m will have a speed of
detailed solution
Correct option is C
Here we have(mv)2+(mv)2=(2mV)2 v2=2V2 or V=v/2Talk to our academic expert!
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Three particles each of mass m are located at vertices of an equilateral triangle ABC. They start moving with equal speeds each along the meridian of the triangle and collide at its center G. If after collisions A comes to rest and B returns its path along GB, then C
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