First slide

The steps in collision

Question

A particle of mass m moving towards the east with speed v collides with another particle of the same mass and same speed v moving towards north. If the two particles stick to each other, the new particle of mass 2 m will have a speed of

Moderate

A

v
B

v/2
C

$V / \sqrt{2}$
D

v $\sqrt{2}$

Solution

Here we have
$(mv)^{2} + (mv)^{2} = (2 mV)^{2} v^{2} = 2 V^{2} or V = v / \sqrt{2}$

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