A particle of mass m is moving with constant velocity v along X-axis in X-Y plane as shown in figure. Its angular momentum with respect to origin at any timet, if position vector is r is
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a
3mvrk
b
3/2⋅mvrk
c
-1/2.mvrk^
d
mvrk
answer is B.
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Detailed Solution
We know that L→ = r→ ×p→ =r cos 600 i^+r sin 600j^×mv i^ = -12mvr k^