A particle of mass m moving with speed v hits elastically another stationary particle of mass 2m inside a smooth horizontal circular tube of mean radius r. The time after which the second collision will take place is
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a
2πrv
b
4πrv
c
3πr2v
d
πrv
answer is A.
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Detailed Solution
In elastic collision, relative speed of separation = relative speed of approach = v∴ Time of next collision =2πrv