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Q.

A particle of mass m moving with speed v hits elastically another stationary particle of mass 2m inside a smooth horizontal circular tube of mean radius r. The time after which the second collision will take place is

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a

2πrv

b

4πrv

c

3πr2v

d

πrv

answer is A.

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Detailed Solution

In elastic collision, relative speed of separation = relative speed of approach = v∴  Time of next collision =2πrv
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