A particle of mass m moving with velocity $$1$$ $$m/s$$ collides perfectly elastically with another stationary particle of mass $$2m$$. If the incident particle is deflected by $$90$$°, the heavy mass will make an angle θ with the initial direction of m equal to

Question

A particle of mass m moving with velocity $$1$$ $$m/s$$ collides perfectly elastically with another stationary particle of mass $$2m$$. If the incident particle is deflected by $$90$$°, the heavy mass will make an angle θ with the initial direction of m equal to

Infinity Learn · Accepted Answer

From conservation of momentum along incident directionm ×$$1$$ $$=$$ $$2$$ $$mv2Cos$$θ                           iFrom conservation of momentum along perpendicular direction,m ×$$0$$ $$+$$ $$2$$ m × $$0$$ $$=$$ $$mv1$$− $$2$$ $$mv2sin$$θ⇒$$v1=$$ $$2v2sin$$θ                        iiFrom energy conservation, $$12m$$×$$(1)2=12mv12+122mv22Solving$$ we get θ $$=$$ $$30$$°.

A particle of mass m moving with velocity 1 m/s collides perfectly elastically with another stationary particle of mass 2m. If the incident particle is deflected by 90°, the heavy mass will make an angle $θ$ with the initial direction of m equal to

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A particle of mass m moving with velocity 1 m/s collides perfectly elastically with another stationary particle of mass 2m. If the incident particle is deflected by 90°, the heavy mass will make an angle θ with the initial direction of m equal to

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A particle of mass m moving with velocity 1 m/s collides perfectly elastically with another stationary particle of mass 2m. If the incident particle is deflected by 90°, the heavy mass will make an angle $θ$ with the initial direction of m equal to