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A particle of mass m moving with velocity 4v collides with another particle of mass 2m moving with velocity v in the same direction. If it is perfect inelastic collision, the loss of K.E. of the system is

a
38mv2
b
278mv2
c
3 mv2
d
zero

detailed solution

Correct option is C

Δu=12M1M2M1+M2(u1−u2)2                 =12×M×2M3M(4v−v)2                 =93Mv2                 =3 mv2

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