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Questions  

A particle of mass m moving in the x-direction with speed 2v is hit by another particle of mass 2m moving in the y-direction with speed v.  If the collision is perfectly inelastic, the percentage loss in the Energy during the collision is close to

a
56 %
b
62 %
c
44 %
d
50 %

detailed solution

Correct option is A

apply law of conservation of linear momentum sum of momentum of both bodies before collision =sum of momentum of both bodies after collision  m 2v⋅i∧ + 2m v⋅j∧  =   (m+2m)⋅v¯' here v¯' if final velocity of both bodies as they stick together∴   v¯'  =    2v3(i∧+j∧) Energy final=Efinal  =   12 (3m)v'2  =   3m2 (223v)2  =    43mv2    ∴     percentage loss of energy=Einitial−EfinalEinitial×100   percentage loss of energy=     3mv2−43mv23mv2 × 100  percentage loss of energy=    59 ×100  percentage loss of energy ≃  56%

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