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A particle of mass m oscillates with simple harmonic motion between points x1  and x2, the equilibrium position being O. Its potential energy is plotted. It will be as given below in the graph 

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detailed solution

Correct option is D

Potential energy of particle performing SHM is given by: PE=12mω2y2 i.e. it varies parabolically such that at mean position it becomes zero and maximum at extreme position.

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The acceleration a of a particle undergoing S.H.M. is shown in the figure. Which of the labelled points corresponds to the particle being at – xmax 


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