A particle of mass m oscillates with simple harmonic motion between points x1 and x2, the equilibrium position being O. Its potential energy is plotted. It will be as given below in the graph
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a
b
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d
answer is D.
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Detailed Solution
Potential energy of particle performing SHM is given by: PE=12mω2y2 i.e. it varies parabolically such that at mean position it becomes zero and maximum at extreme position.