First slide

Gravitaional potential at a point

Question

A particle of mass m is placed at the centre of a thin spherical shell of mass 2m and radius R. Then the gravitational potential at a distance $\frac{R}{2}$ from the centre of the shell is

Easy

A

$- \frac{4 G m}{R}$
B

$- \frac{2 G m}{R}$
C

$- \frac{G m}{R}$
D

$- \frac{3 G m}{R}$

Solution

(1)
V = Potential due to the particle + potential due to the shell.
$= (- \frac{G m}{R / 2}) + (- \frac{G .2 m}{R}) = - \frac{4 G m}{R} .$

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