A particle of mass m is projected from the ground with an initial speed u at an angle α with the horizontal. At the highest point of its trajectory, it makes a completely inelastic collision with another identical particle, which was thrown vertically upward from the ground with the same initial velocity u. The angle that the composite system makes with the horizontal immediately after the collision is
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a
π4
b
π4+α
c
π2−α
d
π2
answer is A.
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Detailed Solution
Velocity at highest point ucosα along horizontal velocity at the same point for the other body V=u2−2gH=u2−u2sin2α2g2g=ucosαAlong vertical direction after inelastic collision mucosα i^+musinα j^=2mV→direction, tanθ=VyVx=1θ=45o=π4