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A particle of mass 'm' is projected with a velocity 'u' at an angle '' with the horizontal. Work done by gravity during its descent from its highest point to, the position where its velocity vector makes an angle α3 with the horizontal is,

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a

12mu2tan2 α

b

12mu2tan2α2

c

12mu2cos2αtan2α2

d

12mu2cos2α2sin2α

answer is C.

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Detailed Solution

As horizontal Component of velocity remains constant, work done = ΔKE along vertical direction , Ky1 = 0Tanα2=VyuCosα⇒Vy=uCosα.Tanα2Ky2=12mVy2=12mu2Cos2α.Tan2α2

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