Questions
A particle of mass m is projected with a velocity u making an angle of 45o with the horizontal. The magnitude of the angular momentum of the projectile about the point of projection when the particle is at its maximum height h is
detailed solution
Correct option is B
ux=ucos45∘=u/2Linear momentum = mu/2Maximum height = u2/4gAngular momentum of the particle=mu2×u24g=mu342gTalk to our academic expert!
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