Questions
A particle of mass m is projected with velocity v at an angle q with the horizontal. Find its angular momentum about the point of projection when it is at
the highest point of its trajectory.
detailed solution
Correct option is A
At the highest point of its trajectory velocity of projectile is v θcos in the horizontal direction and value of maximum height is hmax=v2sin2θ2g∴Angular momentum about the point of projection isL=phmax=(mvcosθ)v2sin2θ2g ⇒L=mv2cosθ⋅sin2θ2g⇒L=mv3sinθ⋅sin2θ4gTalk to our academic expert!
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