Questions
A particle of mass m is projected with a velocity v making an angle of 45o with the horizontal. The magnitude of angular momentum of the projectile about an axis of projection when the particle is at maximum height h is
detailed solution
Correct option is B
0−v2sin245∘=2gh or h=v2/4gAt highest point, momentum=mvcos45∘=mv/2Angular momentum=mv2×h=mv2×v24g=mv342gIn terms of h, angular momentum=mv2×h=m2[(4gh)]×h=m2gh3Talk to our academic expert!
Similar Questions
Assertion : When the velocity of projection of a body is made n times, its time of flight becomes n times.
Reason : Range of projectile does not depend on the initial velocity of a body.
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