Q.
A particle of mass m and q has an initial velocity v→=v0j^ . If an electric field E→=E0i^ and magnetic field B→=B0i^act on the particle, its speed will double after a time:
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a
3mv0qE0
b
2mv0qE0
c
3mv0qE0
d
2mv0qE0
answer is A.
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Detailed Solution
Since, B→ is perpendicular to initial velocity, magnitude of velocity does not change in y−z plane.⇒vo2=vy2+vz2and E→ can accelerate particle only along x axis.⇒ax=qE0mAt any given time speed of particle is , v=vx2+vy2+vz2When speed becomes double, we can write 2vo=vx2+vy2+vz2⇒2vo=vx2+vo2⇒vx=3vo Using equation of kinematics, vx=ux+axt⇒3v0=0+qE0mt⇒t=3mv0qE0
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