Questions
A particle of mass m is released from rest at point A falling parallel to vertical y-axis. Its angular momentum after falling through distance h about O is:
detailed solution
Correct option is A
Angular momentum = (momentum) (perpendicular distance)=(mv)a=ma2ghTalk to our academic expert!
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A particle moving in a circular path has an angular momentum of L. If the frequency of rotation is halved, then its angular momentum becomes [Kerala CEE 2013]
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