A particle of mass M at rest decays into two particles of masses r?11 and m2 having non-zero velocities. The ratio of the de Broglie wavelengths of the particles, λ1,λ2 is

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

m1/m2

m2/m1

1.0

m2/m1

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

According to de Broglie λ=h/mv λ1λ2=h/m1v1h/m2v2=m2v2m1v1 Applying the law of conservation of momentum m1v1=m2v2 From eqs. (1) atrd (2), we Be λ1λ2=m1v1m1v1=1

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET