A particle of mass 3m at rest decays into two particles of masses m and 2m having non-zero velocities. The ratio of the de Broglie wavelengths of the particles (λ1λ2) is
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a
½
b
¼
c
2
d
none of these
answer is D.
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Detailed Solution
From the law of conservation of momentum P1=P2(in opposite direction)Now the de-Broglie wavelength is given by λ=hp.So we can write the required ratio will be equal to 1