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A particle of mass ‘m’ starts with zero velocity and moves along the line y = d . The position of particle  varies as x = A sin ωt. At ωt =π2, its angular momentum with respect to the origin is

a
mAωd
b
mwdA
c
mAdω
d
zero

detailed solution

Correct option is D

velocity of the body v =  Aωcosωt  when ωt =π2, cosωt = 0   v = 0   L→ =r→×p→.  As p=0,  L=0

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