A particle of mass ‘m’ starts with zero velocity and moves along the line y = d . The position of particle varies as x = A sin ωt. At ωt =π2, its angular momentum with respect to the origin is
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a
mAωd
b
mwdA
c
mAdω
d
zero
answer is D.
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Detailed Solution
velocity of the body v = Aωcosωt when ωt =π2, cosωt = 0 v = 0 L→ =r→×p→. As p=0, L=0