Questions
A particle of mass 5 m which is at rest explodes into 3 fragments. Two equal fragments each of mass 2m are found to move with a speed v each in opposite directions. The energy released in the process of explosion is
detailed solution
Correct option is A
From conservation of momentum , 2mV - 2mV+mV'=0 hence v' =0 total kinetic energy=2122mV2 =2mV2Talk to our academic expert!
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A radioactive nucleus initially at rest decays by emitting an electron and neutron at right angles to one another. The momentum of the electron is kgm/s and the momentum of neutron is 6.4 x kgm/sec. The direction of the recoiling nucleus with that of the electron motion is:
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