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Q.

A particle of mass 5 m which is at rest explodes into 3 fragments. Two equal fragments each of mass 2m are found to move with a speed v each in opposite directions. The energy released in the process of explosion is

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a

2mv2

b

32mv2

c

5mv2

d

52mv2

answer is A.

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Detailed Solution

From conservation of momentum , 2mV - 2mV+mV'=0      hence v' =0  total kinetic energy=2122mV2 =2mV2
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