Q.

A particle of mass 2 x 105 kg moves horizontally between two horizontal plates of a charged parallel plate capacitor between which there is an electric field of 200 NC-1 acting upward. A magnetic induction of 2.0 T is applied at right angles to the electric field in a direction normal to both B→ and v→. If g is 9.8 m s-2 and the charge on the particle is 10-6 C, then find the velocity of charge particle so that it continues to move horizontally

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a

2 ms-1

b

20 ms-1

c

0.2 ms-1

d

100 ms-1

answer is A.

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Detailed Solution

Net force on the particle should be zero.qE=10-6×200=2×10-4 Nmg=2×10-5×9.8=1.96×10-4 NSince qE > mg, so magnetic forc e qvB should act downward to balance the forcesqE=mg+qvB⇒2×10-4=1.96×10-4+10-6v×2 ⇒  v=2 m/s
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A particle of mass 2 x 105 kg moves horizontally between two horizontal plates of a charged parallel plate capacitor between which there is an electric field of 200 NC-1 acting upward. A magnetic induction of 2.0 T is applied at right angles to the electric field in a direction normal to both B→ and v→. If g is 9.8 m s-2 and the charge on the particle is 10-6 C, then find the velocity of charge particle so that it continues to move horizontally