A particle moved from position r1 → = 3i^ +2j^-6k^ to position r2→ = 14i^+13j^ + 9 k^ under the action of a force (4i^+j^+3k^) newtons. Find the work done.

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

answer is 2.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

displacement : s→ = r2→ -r1→. Now find W = F→ .s→ s→= 14i^+13j^+9k^-3i^-2j^+6k^ =11i^+11j^+15k^W = 44+11+45 = 100 J

Watch 3-min video & get full concept clarity