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A particle moves along a circle of radius 20πm with constant tangential acceleration. It the velocity of the particle is 80 m/s at the end of the second revolution after motion has begun, the tangential acceleration is

a
640πm/s2
b
160πm/s2
c
40πm/s2
d
40m/s2

detailed solution

Correct option is D

In case of circular motion,ω2−ω02=2αθ âˆµv2−u2=2asω2=2αθ âˆµÏ‰0=0or      vr2=2arθ (∵a=rα)or      a=V22rθGiven that r = (20/π) metre, V = 80 m/s and θ = 4π radian.Substituting these values, we geta=40m/s2

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