Questions
A particle moves along a horizontal path, such that its velocity is given by where is the time in seconds. If it is initially located at the origin , determine the distance travelled by the particle in time interval from to and the particle's average velocity and average speed during the same time interval.
detailed solution
Correct option is B
⇒ v=0 at t=2 sFor t<2 s, velocity is negative. At t=2 s, velocity is zero and for t=2 s velocity is positive.s1=∫015vdt=∫01s3t2-6tdt =6.125 m = displacement upto 3.5 s s2=∫02vdt=∫023t2-6tdt =-4 m = displacement upto 2 s ∴ d= distance travelled in 3.5 s =4+4+6.125 =14.125 m Average speed =dt=14.1253.5 =4.03 m/s Average velocity =s1t=6.1253.5 =1.75 m/s.Talk to our academic expert!
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A particle starts moving along a straight line path with a velocity 10 m s-1. After 5 s, the distance of the particle from the starting point is 50 m. Which of the following statement about the nature of motion of the particle are correct?
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