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Q.

A particle moves along positive branch of the curve, y=x2, where x=t33, x and y are measured in meters and t, in seconds, then

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a

The velocity of particle at t=1s is i^+12j^.

b

The velocity of particle at t=1s is 12i^+j^.

c

The acceleration of particle at t=1s is 2i^+j^.

d

The acceleration of particle at t=1s is i^+2j^.

answer is A.

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Detailed Solution

dxdt=t2   ........(i) y=12t33⇒dydt=t22  .........(ii) t=1,vx=1,vy=12⇒v→=i^+12j^ d2xdt2=2t  ........(iii) d2ydt2=t    ..........(iv)  At t=1s,ax=2  and  ay=1 ⇒ a→=2i^+j^
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