Q.
A particle moves along positive branch of the curve, y=x2, where x=t33, x and y are measured in meters and t, in seconds, then
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a
The velocity of particle at t=1s is i^+12j^.
b
The velocity of particle at t=1s is 12i^+j^.
c
The acceleration of particle at t=1s is 2i^+j^.
d
The acceleration of particle at t=1s is i^+2j^.
answer is A.
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Detailed Solution
dxdt=t2 ........(i) y=12t33⇒dydt=t22 .........(ii) t=1,vx=1,vy=12⇒v→=i^+12j^ d2xdt2=2t ........(iii) d2ydt2=t ..........(iv) At t=1s,ax=2 and ay=1 ⇒ a→=2i^+j^
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