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A particle moves along a straight line such that its displacement at any time t is given by s = (t3- 6t2 + 3t + 4)meters. The velocity when the acceleration is zero is

a
3m/s
b
42m/s
c
–9m/s
d
–15m/s

detailed solution

Correct option is C

S = (t3 - 6t2 + 3t + 4)V = ds/dt ⇒ V = 3t2 -12t + 3a = dv/dt ⇒ a = 6t - 12When a = 0 ; t = 2secV = 3(2)2 - 12(2) + 3 = -9m/sec

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