A particle moves along x -axis with initial position x=0. Its velocity varies with x-coordinate as shown in graph. The acceleration 'a' of this particle varies with x as -
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answer is A.
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Detailed Solution
v=−mx+C where m and C are positive constants. ∴ Acceleration, a=vdvdx=−m(−mx+C)⇒a=m2x−mCStraight line with positive slope and negative y intercept