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Questions  

A particle moves along the x-axis and its x-coordinate changes with time as x=u(t2)+a(t2)2

a
the initial velocity of the particle is u
b
the acceleration of the particle is a
c
the acceleration of the particle is 2a
d
at t = 2s particle is at the origin

detailed solution

Correct option is C

x=ut-2+at-22 Therefore v=dxdt=u+2at-2 and a=dvdt=2a At t=0, v=u At t= 2 s, x=0

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