A particle moves along the x-axis and its x-coordinate changes with time as x=u(t−2)+a(t−2)2

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the initial velocity of the particle is u

the acceleration of the particle is a

the acceleration of the particle is 2a

at t = 2s particle is at the origin

answer is C.

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Detailed Solution

x=ut-2+at-22 Therefore v=dxdt=u+2at-2 and a=dvdt=2a At t=0, v=u At t= 2 s, x=0

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