A particle moves along the X-axis with its position x given as a function of time t by the equation x= -bt+ct2, where b and c are positive constants. At what time, the velocity of the particle will be equal in magnitude and opposite in direction to its initial velocity?
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a
at t = b/2c
b
at t = 2b/c
c
at t = b/c
d
at t = b/4c
answer is C.
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Detailed Solution
Comparing with x=ut+(1/2)at2, we get u = -b and a = 2c. Using v = u + at, b = -b +2ct which gives t = b/c