Q.
A particle moves in a circle of radius 25 cm at two revolutions per sec. The acceleration of the particle in m/s2 is:
see full answer
Start JEE / NEET / Foundation preparation at rupees 99/day !!
21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya
a
π2
b
8 π2
c
4π2
d
2π2
answer is C.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
r = 25 × 10-2 m, f = 2 /sec ω = 2πf= 4π rad/secAcceleration = ω2 r = (4π)2×25×10-2 = 16×25×10-2π2 m/s2 = 4π2 m/s2
Watch 3-min video & get full concept clarity