A particle moves in a circle of radius 5 cm with constant speed and time period 0.2 π s. The acceleration of the particle is

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25 m/s2

36 m/s2

5 m/s2

15 m/s2

answer is C.

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Detailed Solution

Given, r = 5 cm = 5 ×10-2m and T = 0.2 πsWe know that acceleration a = rω2 = 4π2T2r= 4×π2×5×10-2(0.2 π)2 = 5 ms-2

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