Questions
A particle moves in a circle of radius 5 cm with constant speed and time period 0.2 The acceleration of the particle is
detailed solution
Correct option is C
Given, r = 5 cm = 5 ×10-2m and T = 0.2 πsWe know that acceleration a = rω2 = 4π2T2r= 4×π2×5×10-2(0.2 π)2 = 5 ms-2Talk to our academic expert!
Similar Questions
A particle moves along a horizontal circle with constant speed. If 'a' is its acceleration and 'E' is its kinetic energy
A) a is constant B) E is constant C) a is variable D) E is variable
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