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Q.

A particle moves from a point(-2i^+5j^) to (4j^+3k^)  when a force of (4i^+3j^) N is applied. How much work has been done by the force?

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a

8 J

b

5 J

c

11 J

d

2 J

answer is B.

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Detailed Solution

Here r→1=(-2i^+5j^)m,r→2=(4j^+3k^)mF→=(4i^+3j^)N,W=? Work done by force F in moving from r→1 to r→2 , W=F→·r→2-r→1W=(4i^+3j^)·(4j^+3k^+2i^-5j^)=(4i^+3j^)·(2i^-j^+3k^)=8+(-3)=5 J
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