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A particle moves from point A (5, 6) to point B (3, 4) under the influence of a constant force F→=(2i^+bj^) N. If the speed of the particle remains constant, then the value of ‘b’ (in N) is

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Detailed Solution

Displacement, d→=(3−5)i^+(4−6)j^ m=-2i^-2j^W = work done=F→.d→=2(−2)+b(−2)=(−4−2b)Since kinetic energy remains constant, W=0⇒−4−2b=0⇒b=−2

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