Questions
A particle moves so that its acceleration a is given by , where is displacement from the equilibrium position and b is a constant. The period of oscillation is
detailed solution
Correct option is B
Condition for motion of a particle to be SHM is, acceleration of SHM is a = −ω2x, here ω= angular velocity, x= displacementGiven equation , a = −bx ∴ ω2=b ω=b, time period is T2πT=b ⇒T=2πbTalk to our academic expert!
Similar Questions
A body executes S.H.M. under the action of a force F1 with a time period 7/6 seconds. If the force is changed to F2 it executes S.H.M. with time period 7/8 seconds. If both the forces F1 and F2 act simultaneously in the same direction on the body, then its time period in seconds is
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