A particle moves in a straight line with retardation proportional to its displacement. Its loss of kinetic energy for any displacement x is proportional to
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a
x2
b
ex
c
x
d
loge x
answer is A.
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Detailed Solution
Here, a=−kx, where a is acceleration, x is displacement and k is proportionality constant. ∴ vdvdx=−kx Vdv=−kxdx Integrating within proper limits, we get ∫v0v vdv=−k∫0x xdx v22v0v=−kx220x v2−v022=−kx22 multiplying m on both sides, we get m v2−v022=−mkx22∞x2 Δk=−mkx22∝x2