Questions
A particle moves in a straight line with the velocity as shown in figure. At t = 0, x = -16 m.
a
The maximum value of the position coordinate of the particle is 54 m.
b
The maximum value of the position coordinate of the particle is 36 m.
c
The particle is at the position of 36 m at t = 18 s.
d
The particle is at the position of 36 m at t = 30 s.
detailed solution
Correct option is A
Maximum value of position coordinate - Initial coordinate + Area under the graph up to t = 24 s (As up to t = 24 s, the displacement of the particle will be positive (figure).Maximum value of position coordinate =−16+(2×10)+2+62×(18−10)+1×62×(24−18)=−16+[20+32+18]=54mAt time t=18sPosition=−16+ Area of graph up to t=18s =−16+[20+32+18]=54mAt time t=30sPosition=−16+ Area of graph up to t=30s =−16+70−12×6×6=36mTalk to our academic expert!
Similar Questions
The acceleration versus time graph of a particle is shown in figure. The respective v-t graph of the particle is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
Popular Books
HC Verma Part 1HC Verma Part 2RS AgarwalRD SharmaLakhmir SinghDK GoelSandeep GargTS GrewalNCERT solutions
Class 12 NCERT SolutionsClass 11 NCERT SolutionsClass 10 NCERT SolutionsClass 9 NCERT SolutionsClass 8 NCERT SolutionsClass 7 NCERT SolutionsClass 6 NCERT Solutions
