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A particle moves in a straight line with the velocity as shown in figure. At t = 0, x = -16 m.

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By Expert Faculty of Sri Chaitanya
a
The maximum value of the position coordinate of the particle is 54 m.
b
The maximum value of the position coordinate of the particle is 36 m.
c
The particle is at the position of 36 m at t = 18 s.
d
The particle is at the position of 36 m at t = 30 s.
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detailed solution

Correct option is A

Maximum value of position coordinate - Initial coordinate + Area under the graph up to t = 24 s (As up to t = 24 s, the displacement of the particle will be positive (figure).Maximum value of position coordinate              =−16+(2×10)+2+62×(18−10)+1×62×(24−18)=−16+[20+32+18]=54mAt time t=18sPosition=−16+ Area of graph up to t=18s =−16+[20+32+18]=54mAt time t=30sPosition=−16+ Area of graph up to t=30s =−16+70−12×6×6=36m

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