A particle moves such that its acceleration is given by : a =-βx-2 Here β is a positive constant and x the position from origin. Time period of oscillations is

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2πβ

2π1β

2πβ+2

2π1β+2

answer is B.

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Detailed Solution

a = o at x = 2 i.e. x = 2 is the mean position. Assuming x – 2 = X a = -βX i.e. a∞- X ; a=-ω2X ω2=β T=2πω =2πβ

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