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Q.

A particle moves such that its acceleration is given by : a =-βx-2  Here  β is a positive constant and x the position from origin. Time period of oscillations is

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a

2πβ

b

2π1β

c

2πβ+2

d

2π1β+2

answer is B.

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Detailed Solution

a = o at x = 2 i.e. x = 2 is the mean position.                         Assuming      x – 2 = X                                                a =  -βX        i.e.  a∞- X ;        a=-ω2X         ω2=β   T=2πω =2πβ
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