A particle moves such that its acceleration is given by : a =-βx-2 Here β is a positive constant and x the position from origin. Time period of oscillations is
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a
2πβ
b
2π1β
c
2πβ+2
d
2π1β+2
answer is B.
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Detailed Solution
a = o at x = 2 i.e. x = 2 is the mean position. Assuming x – 2 = X a = -βX i.e. a∞- X ; a=-ω2X ω2=β T=2πω =2πβ