Q.

A particle moves such that its position vector r→t=cosωt  i^+sinωt  j^  where  ω is a constant and t is time. Then which of the following statements is true for the velocity ν→t  and a→tacceleration   of the particle :

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a

ν→  is perpendicular to  r→ and a→ is directed towards the origin

b

ν→  is perpendicular to  r→ and a→  is directed away from the origin

c

ν→  and a→  both are parallel to  r→

d

ν→  and a→  both are perpendicular to  r→

answer is A.

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Detailed Solution

r→=cosωti∧+sinωtj∧​⇒v→=dr→dt=ω−sinωti∧+cosωtj∧​⇒a→=dv→dt=ω2−cosωti∧−sinωtj∧⇒a→=−ω2cosωti∧+sinωtj∧​⇒a→=−ω2r→​∴a→ is anti parallel to r→r→ is radially outward​So, a→ is radially inward​​Also., v→.r→=ω−sinωtcosωt+cosωtsinωt=0So v→ ⊥r→
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