A particle moves such that its position vector r→t=cosωt i^+sinωt j^ where ω is a constant and t is time. Then which of the following statements is true for the velocity ν→t and a→tacceleration of the particle :
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a
ν→ is perpendicular to r→ and a→ is directed towards the origin
b
ν→ is perpendicular to r→ and a→ is directed away from the origin
c
ν→ and a→ both are parallel to r→
d
ν→ and a→ both are perpendicular to r→
answer is A.
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Detailed Solution
r→=cosωti∧+sinωtj∧⇒v→=dr→dt=ω−sinωti∧+cosωtj∧⇒a→=dv→dt=ω2−cosωti∧−sinωtj∧⇒a→=−ω2cosωti∧+sinωtj∧⇒a→=−ω2r→∴a→ is anti parallel to r→r→ is radially outwardSo, a→ is radially inwardAlso., v→.r→=ω−sinωtcosωt+cosωtsinωt=0So v→ ⊥r→